Summary
This lesson opens the unit devoted to complex numbers in polar form. It presents its six lessons and the thread that unites them: describing each complex number by its distance from the origin and by its direction turns the product into a rotation composed with a dilation, powers into multiples of an angle and roots into regular polygons. It reconstructs the historical background of these ideas, from the formula for the cubic published by Cardano in 1545 and Bombelli’s rules of calculation to the geometric representation of Wessel, Argand and Gauss and Euler’s formula; it poses the twofold problem that gave rise to them, algebraic and geometric, which the example of the mean proportional between and sums up, and points out where they are used later, in this course, in other courses on the site and in science and technology.
Learning objectives
- Describe the content of each lesson of the unit and explain why they follow one another in that order.
- Recount, with its protagonists and their approximate dates, the transition of complex numbers from a computational device to a geometric object, from Cardano and Bombelli to Wessel, Argand, Gauss and Euler.
- State the algebraic problem and the geometric problem that gave rise to the polar form, and interpret as rotations the product by and the mean proportionals between and .
- Identify the applications of the polar form in the following unit, in other courses on the site and in physics and engineering.
Entry assessment
Before working through the unit, it is advisable to measure the starting point. This self-assessment does not grade: it serves to show what has been mastered and where to slow down. The first ten questions cover the six content lessons of the unit: one the lesson on the polar form and another the one on geometry with complex numbers; two each the lessons on De Moivre’s formula, on roots and on polynomial equations; and two the one on the complex exponential, the second of them a modeling problem, which asks for a situation in context to be set up with phasors. The same skills are measured again at the end, in the synthesis lesson. The last two check what the unit takes as known from Course I and from the earlier units: the rectangular form, the conjugate and the modulus, the special values and the sum and difference formulas.
Before starting the unit, measure your starting point. It is a short self-assessment: it is not graded and its result is stored only in your browser.
Question 1What is the principal argument of ?
It is the arctangent of the quotient without correction: the arctangent only sees the first and fourth quadrants, and is the argument of the opposite point, .It is an argument of , but not the principal one, because it does not lie in ; the principal one is obtained by subtracting a full turn from it.It is the argument of , in the fourth quadrant: the sign of the imaginary part has been taken into account, but not that of the real part.The point lies in the third quadrant. The arctangent of is , and since the real part and the imaginary part are negative, the formula subtracts : , which lies in .Question 2Compute .
Correct answer:
The number has modulus and argument . By De Moivre’s formula, the sixth power has modulus and argument : it is . Whoever gets has forgotten that the argument corresponds to the negative real half-axis.Question 3What is the linearization of ?
It has been multiplied by instead of by : the in is squared as well. With it would give , and the product equals .The power has been reduced with the cosine formula; the sine formula carries a minus sign, . With it would give , and the product equals .The power has been reduced without doubling the angle: the square of is linearized with the cosine of , not of .With , the product is ; hence , and squaring and reducing the power gives . With , both sides equal .Question 4Which of these numbers is a fourth root of ?
It has the correct modulus, but its argument is half of , not a quarter of it: , not .This is the sign rule for real roots of odd index, which does not apply here: a real number raised to an even power is not negative, and .The argument is correctly divided, but the modulus has also been divided by , when its fourth root should have been taken: the fourth power of this number is .The number has modulus and argument ; its fourth roots have modulus and arguments . With one obtains .Review: The nth roots of a complex number and the roots of unity
Question 5How many primitive ninth roots of unity are there?
Correct answer:
The root , with , is primitive if and only if ; the natural numbers up to that are coprime to are , , , , and . Whoever gets has treated as if it were prime; the roots and are cube roots of unity, and their powers visit only three roots.Review: The nth roots of a complex number and the roots of unity
Question 6Which complex numbers satisfy ?
It is a solution of , not of . The minus sign requires the argument of to be , up to full turns, and periodicity gives infinitely many solutions.These are the solutions of : the argument of the number is missing.The real exponential is; the complex one takes all nonzero values, because the imaginary part of the exponent fixes an arbitrary direction.The number has modulus and argument . If , the modulus of is and is an argument of it: gives , and differs from by an integer multiple of .Question 7Two loudspeakers emit the same pure tone. At the place where the listener is, the pressure variations they produce are and , in millipascals. What is the amplitude of the total pressure variation, in millipascals?
Correct answer:
Each oscillation is the real part of its phasor multiplied by , and the sum of two oscillations of the same frequency has as its phasor the sum of the phasors: , whose modulus is . Whoever gets has added the amplitudes, as if the maxima coincided; whoever gets has subtracted them, as if the oscillations were in phase opposition; and whoever gets has treated the phasors as perpendicular.Question 8What is the image of the point under the quarter-turn rotation, in the positive direction, about the point ?
It is , the rotation about the origin. To rotate about another center, one must subtract it before multiplying by and add it back afterward.It is the rotation in the negative direction, clockwise, which multiplies by : the positive direction corresponds to multiplying by .The number has been added to the point instead of to the center: the image is the center plus the rotated vector.The rotation about through the angle is . Here , its rotation is , and the image is .Review: Geometry with complex numbers
Question 9Let , and be the roots of . Compute .
Correct answer:
By Vieta’s formulas, and , and the sum of the squares is . That it is negative indicates that not all the roots are real. Whoever gets has confused the sum of the squares with the square of the sum, and whoever gets has added instead of subtracting it.Review: Complex polynomial equations: the Cardano and Ferrari formulas
Question 10What are the roots of the equation like?
This corresponds to . The sign has been miscalculated: with , the term is negative, and turns out positive.This requires , that is, , which does not happen here.A cubic with real coefficients always has a real root, because its nonreal roots form conjugate pairs and there are three in all.The discriminant is , positive; this is the irreducible case, in which Cardano’s formula passes through cube roots of nonreal numbers even though the three roots are real.Review: Complex polynomial equations: the Cardano and Ferrari formulas
Question 11From earlier unitsWhat is the inverse of ?
It has been divided by the modulus and not by its square: the product equals , not .The real part and the imaginary part have been inverted separately; the inverse of a sum is not the sum of the inverses.The conjugate of is : conjugating changes the sign of the imaginary part, and only that one.The inverse of is ; here and . Check: .Question 12From earlier unitsWhat is the exact value of ?
It is the cosine of : in the sine of a difference the two products are subtracted.It is : the sine of a difference is not the difference of the sines.It is the sine of , twice the requested angle; the sine is not proportional to the angle.Since , by the formula for the sine of a difference and the special values, .Review: Sum and difference formulas, double angle and half angle
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